Can anybody answer the following Chemistry problem?

D. The volume of the sphere is 65.450 cm^3 (V=4/3pi*r^3). It displaces, when fully submerged, a mass of 65.45 cm^3*0.879 g/ cm^3 = 57.530 g of benzene. This is equal to the 12 g mass of the vessel plus 45.530 g of water. Divide by the density of water of 1 g/cm^3, we have 45.530 cm^3 , and since one cm^3 = 1 mL, the correct answer is D. That would be the correct answer even after including the mass of the air filling the rest of the vessel, assuming that's what's in with the water.